$algebra 2 systems of equations$

ALGEBRA 2 SYSTEMS OF EQUATIONS PLUS

This a little bit neater, let me actually delete, let me make these line up a little bit better Now we can just add the left and right hand sides of these two equations.

$algebra 2 systems of equations$

Going to be equal to 1.5 times negative five is It's going to be negative five over 60, that's negativeġ/12, so this is negative B over 12 and then it is Sides by negative five I'm going to get negativeįive times W over five is negative W, negativeįive times B over 60. Sides by negative five, I'm going to multiply both If I multiply both sides by negative five, so both Switch to one color here, so this top equation is going

Multiply the second equation by, I'm just gonna This second equation by negative five, and I'm gonna, this is going to be a negative W here so it'll cancel out with this W up there. Now what's an easy thing to do? Let's see, if I can multiply We should be able to find W and B that satisfy both of these. We have two linearĮquations with two unknowns. This is all going to be in hours and now we can solve Going to be the distance on the bus divided by,ĭivided by the average speed of the school bus, so So his time walking is W over five, W over five and by that same logic, his time on the bus is Going to be the same thing, this is gonna be W over five If you have one over hours in the denominator, that's Hour and so you're gonna have kilometers cancel kilometers and if you divide by or So the distance walking is W kilometers W kilometers divided by his rate, the distance divided by your rate is gonna give you your time, so let's see, his rate is five kilometers per hour, five kilometers per What's the time traveled by, what's the time he walks? Let me write this over here, time time walking, we'll that's going to be the distance walkingĭivided by the rate walking. So the total amount of time is going to be one and half hours, so we'll

ALGEBRA 2 SYSTEMS OF EQUATIONS PLUS

We know that W plus B, W plus B, plus B isĮqual to 35 kilometers, is equal to 35 kilometersĪnd just with one equation, we're not going to be able toįigure out what W and B are but we have another constraint. Is the entire distance from home to school, so So what do we know? We know the distance covered by walking plus the distance covered by bus is going to be 35 kilometers,ģ5 kilometers here, this is the entire, that The rest of this distance, all of this distance right over there, that is going to be B. So this right over here, thisĭistance, right over here, that is W and the rest of the distance, he covered by the bus, so One and a half hours, now he traveled at different rates forĭistance to the school bus so this is, or to the bus stop, so that's the bus stop, right over there, and we're seeing thisĭistance to the bus stop, that's how much he covered by walking. I'll draw a biggerīuilding, that's his school, and we know that thisĭistance is 35, 35 kilometers and we also know that it Travel and see they tell us, they tell us that it isģ5 kilometers to school so this is his school right over here. His home, that's his home and then he is going to He cover by walking? Let's call this W and how many kilometers did he cover by travelling on the bus? Let's call that, Let's call that B and so what do we know? We know that the kilometers and I can actually evenĭraw it just to make sure that we're visualizing this thing, right? So this right over here is Alright, so let's justĭefine some variables here. So I encourage you to pause the video and try to think about on your own. How many kilometers did Yochanan cover by walking, and how many kilometers did he cover by travelling The total distance from his home to school is 35 kilometers, and the entire trip took one and a half hours. He immediately got on his school bus and traveled at an average speed of 60 kilometers per hour From home to the bus stop at an average speed ofįive kilometers per hour.

Algebra 2 systems of equations